B1010一元多项式求导 (25)

#include<cstdio>int main(){int s[1001] = {0};int a,b,count = 0;while(scanf("%d %d",&a,&b)!=EOF){s[b] = a;}s[0] = 0;      //注意置零for(int i = 1;i < 1001;i++){if(s[i]){s[i-1] = s[i]*i;s[i] = 0;}}for(int i = 1000;i >= 0;i--){if(s[i]){if(count) printf(" ");printf("%d %d",s[i],i);count++;}}if(!count) printf("0 0\n");   //特判return 0;}