HDU 1030

具体分析是借鉴hdu1030 数学题 - To be an ACMan - 博客园
http://www.cnblogs.com/ACMan/archive/2012/05/30/2526798.html

#include<iostream>#include<cmath>using namespace std;int main(){    int m,n;    int m1,m2,m3,n1,n2,n3;    while(cin>>m>>n){        m1=ceil(sqrt(m));        m2=(m-(m1-1)*(m1-1)-1)/2+1;        m3=(m1*m1-m)/2+1;        n1=ceil(sqrt(n));        n2=(n-(n1-1)*(n1-1)-1)/2+1;        n3=(n1*n1-n)/2+1;        cout<<abs(m1-n1)+abs(m2-n2)+abs(m3-n3)<<endl;    }    return 0;}