CF_560B_GeraldIsIntoArt

B. Gerald is into Art

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board has shape of an a₁ × b₁ rectangle, the paintings have shape of a a₂ × b₂ and a₃ × b₃ rectangles.

Since the paintings are painted in the style of abstract art, it does not matter exactly how they will be rotated, but still, one side of both the board, and each of the paintings must be parallel to the floor. The paintings can touch each other and the edges of the board, but can not overlap or go beyond the edge of the board. Gerald asks whether it is possible to place the paintings on the board, or is the board he bought not large enough?

Input

The first line contains two space-separated numbers a₁ and b₁ — the sides of the board. Next two lines contain numbers a₂, b₂, a₃ andb₃ — the sides of the paintings. All numbers a_i, b_i in the input are integers and fit into the range from 1 to 1000.

Output

If the paintings can be placed on the wall, print "YES" (without the quotes), and if they cannot, print "NO" (without the quotes).

Sample test(s)

input

3 21 32 1

output

YES

input

5 53 33 3

output

NO

input

4 22 31 2

output

YES

Note

That's how we can place the pictures in the first test:

And that's how we can do it in the third one.

简单问题

一幅画放在左上一幅画放在右下

要么长的和小于总长宽各自小于总宽

要么宽的和小于总宽长各自小于总长

注意可以旋转，多判下就可以了

#include <iostream>#include <stdio.h>using namespace std;int main(){    int a1,a2;    int a3,a4;    int a5,a6;    int f=0;    scanf("%d%d%d%d%d%d",&a1,&a2,&a3,&a4,&a5,&a6);    if(a3+a5<=a1&&a4<=a2&&a6<=a2)        f=1;    if(a3+a5<=a2&&a4<=a1&&a6<=a1)        f=1;    if(a3+a6<=a1&&a4<=a2&&a5<=a2)        f=1;    if(a3+a6<=a2&&a4<=a1&&a5<=a1)        f=1;    if(a4+a5<=a1&&a3<=a2&&a6<=a2)        f=1;    if(a4+a5<=a2&&a3<=a1&&a6<=a1)        f=1;    if(a4+a6<=a1&&a3<=a2&&a5<=a2)        f=1;    if(a4+a6<=a2&&a3<=a1&&a5<=a1)        f=1;    if(f)        printf("YES\n");    else        printf("NO\n");    return 0;}