MOOC:计算机科学及Python编程导论
来源:互联网 发布:surface pro知乎 编辑:程序博客网 时间:2024/05/29 03:31
Study : Introduction to Computer Science and Programming Using Python
Problem Set 3 hangman:
# 6.00 Problem Set 3# # Hangman game## -----------------------------------# Helper code# You don't need to understand this helper code,# but you will have to know how to use the functions# (so be sure to read the docstrings!)import randomimport stringWORDLIST_FILENAME = "C:/Users/y50/6.00.1x Files/words.txt"def loadWords(): """ Returns a list of valid words. Words are strings of lowercase letters. Depending on the size of the word list, this function may take a while to finish. """ print "Loading word list from file..." # inFile: file inFile = open(WORDLIST_FILENAME, 'r', 0) # line: string line = inFile.readline() # wordlist: list of strings wordlist = string.split(line) print " ", len(wordlist), "words loaded." return wordlistdef chooseWord(wordlist): """ wordlist (list): list of words (strings) Returns a word from wordlist at random """ return random.choice(wordlist)# end of helper code# -----------------------------------# Load the list of words into the variable wordlist# so that it can be accessed from anywhere in the programwordlist = loadWords()def isWordGuessed(secretWord, lettersGuessed): ''' secretWord: string, the word the user is guessing lettersGuessed: list, what letters have been guessed so far returns: boolean, True if all the letters of secretWord are in lettersGuessed; False otherwise ''' # FILL IN YOUR CODE HERE... i=0 n=0 copy=[] num=range(len(secretWord)) for letter in secretWord: copy.append(letter) while i<len(lettersGuessed): count=0 if lettersGuessed[i] in secretWord: for letter in copy: if letter==lettersGuessed[i]: count+=1 num.remove(copy.index(lettersGuessed[i])) if count>1: while n<(count-1): copy[copy.index(lettersGuessed[i])]=0 num.remove(copy.index(lettersGuessed[i])) n+=1 i+=1 if num==[]: return True return Falsedef getGuessedWord(secretWord, lettersGuessed): ''' secretWord: string, the word the user is guessing lettersGuessed: list, what letters have been guessed so far returns: string, comprised of letters and underscores that represents what letters in secretWord have been guessed so far.>>> secretWord = 'apple' >>> lettersGuessed = ['e', 'i', 'k', 'p', 'r', 's']>>> print getGuessedWord(secretWord, lettersGuessed)'_ pp_ e' ''' # FILL IN YOUR CODE HERE... i=0 n=0 copy=[] copy1=['_ ']*len(secretWord) for letter in secretWord: copy.append(letter) while i<len(lettersGuessed): count=0 if lettersGuessed[i] in secretWord: for letter in copy: if letter==lettersGuessed[i]: count+=1 if count==1: copy1[copy.index(lettersGuessed[i])]=lettersGuessed[i] elif count>1: while n<count: copy1[copy.index(lettersGuessed[i])]=lettersGuessed[i] copy[copy.index(lettersGuessed[i])]=0 n+=1 i+=1 if copy1==copy: a=''.join(copy1) return a a=''.join(copy1) return adef getAvailableLetters(lettersGuessed): ''' lettersGuessed: list, what letters have been guessed so far returns: string, comprised of letters that represents what letters have not yet been guessed. ''' # FILL IN YOUR CODE HERE... allletter=string.ascii_lowercase copy=[] for letter in allletter: copy.append(letter) for letter in lettersGuessed: copy.remove(letter) availableletters=''.join(copy) return availablelettersdef hangman(secretWord): ''' secretWord: string, the secret word to guess. Starts up an interactive game of Hangman. * At the start of the game, let the user know how many letters the secretWord contains. * Ask the user to supply one guess (i.e. letter) per round. * The user should receive feedback immediately after each guess about whether their guess appears in the computers word. * After each round, you should also display to the user the partially guessed word so far, as well as letters that the user has not yet guessed. Follows the other limitations detailed in the problem write-up. ''' # FILL IN YOUR CODE HERE... lettersGuessed=[] mistakesMade=0 maxguess=8 print('Welcome to the game, Hangman!') print('I am thinking of a word that is '+str(len(secretWord))+' letters long.') while mistakesMade<maxguess: print('You have '+str(maxguess-mistakesMade)+' guesses left.') print('Available letters: '+getAvailableLetters(lettersGuessed)) guess=raw_input('Please guess a letter: ') guessInLowerCase = guess.lower() if guessInLowerCase in lettersGuessed: print("Oops! You've already guessed that letter: "+getGuessedWord(secretWord, lettersGuessed)) else: lettersGuessed.append(guessInLowerCase) if guessInLowerCase in secretWord: print("Good guess: " +getGuessedWord(secretWord, lettersGuessed)) if isWordGuessed(secretWord, lettersGuessed): break else: print("Oops! That letter is not in my word: " +getGuessedWord(secretWord, lettersGuessed)) mistakesMade+=1 if isWordGuessed(secretWord, lettersGuessed): print('Congratulations, you won!') else: print('Sorry, you ran out of guesses. The word was else. ') print('The word was: '+secretWord)# When you've completed your hangman function, uncomment these two lines# and run this file to test! (hint: you might want to pick your own# secretWord while you're testing)# secretWord = chooseWord(wordlist).lower()# hangman(secretWord)def game(): hangman(chooseWord(wordlist))
0 0
- MOOC:计算机科学及Python编程导论
- MIT 计算机科学和Python 编程导论
- 麻省理工开放课程:计算机科学及编程导论
- 麻省理工开放课程:计算机科学及编程导论
- mit 计算机科学及编程导论(1)
- mit 计算机科学及编程导论(2)
- mit 计算机科学及编程导论(3)
- mit 计算机科学及编程导论(4)
- mit 计算机科学及编程导论(5)
- mit 计算机科学及编程导论(6)
- mit 计算机科学及编程导论(7)
- mit 计算机科学及编程导论(8)
- mit 计算机科学及编程导论(9)
- mit 计算机科学及编程导论(10)
- mit 计算机科学及编程导论(11)
- mit 计算机科学及编程导论(12)
- mit 计算机科学及编程导论(13)
- MIT公开课---计算机科学及编程导论
- Andorid屏幕分辨率划分规则 dpi
- 《机器学习实战》k最近邻算法(K-Nearest Neighbor,Python实现)
- Failed to load JavaHL Library解决方法
- android 下拉刷新的layout,继承后只需要关注不同状态时headerView的变化
- oc和swift混编 (整理的链接)
- MOOC:计算机科学及Python编程导论
- jQuery 实现点击空白关闭目标元素的实现方法
- 搜集到的面试题。
- Linux 查找nginx access_log 并删除一个月之前的log
- Java 多线程学习笔记
- ucos iii在zynq上的移植
- 局部变量被内部类访问时必须用final修饰的问题
- JS特殊字符判断
- 如果让我重新设计一款App