【leetcode每日一题】NO21.Merge Two Sorted Lists
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题目:Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
解析:与有序数组合并类似,先声明一个指针,指向值小的头结点,再遍历两个指针,依次比较大小。
代码:
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public: ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { if(l1==NULL) return l2; if(l2==NULL) return l1; ListNode *result,*curNode; if(l1->val<l2->val) { result=curNode=l1; l1=l1->next; } else { result=curNode=l2; l2=l2->next; } while(l1!=NULL&&l2!=NULL) { if(l1->val<l2->val) { curNode->next=l1; l1=l1->next; curNode=curNode->next; } else { curNode->next=l2; l2=l2->next; curNode=curNode->next; } } while(l1!=NULL) { curNode->next=l1; l1=l1->next; curNode=curNode->next; } while(l2!=NULL) { curNode->next=l2; l2=l2->next; curNode=curNode->next; } return result; }};
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