LeetCode题解：Rectangle Area

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Assume that the total area is never beyond the maximum possible value of int.

题意：求出两个交叠矩形的面积

解决思路：矩形总面积减去交叠区域面积

代码：

public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {        int together;        if (C <= E || A >= G || B >= H || D <= F) {            together = 0;        } else {            int x = Math.min(C, G) - Math.max(A, E);            int y = Math.min(D, H) - Math.max(B, F);            together = x * y;        }        return (C - A) * (D - B) + (G - E) * (H - F) - together;    }