hdu2199 Can you solve this equation?(二分查找,多项式求解)
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题目链接:点击打开链接
题目描述:给定一个单调多项式,问在[0,100]是否存在值满足多项式等于某个值?
解题思路:二分查找
注意:题目给出精确到4位小数即可,所以eps为6即可,否则会TLE
代码:
#include <cstdio>#include <cmath>#define eps 1e-5///注意事项,精度问题,太高容易超时using namespace std;double cal(double x){ return (8*x*x*x*x+7*x*x*x+2*x*x+3*x+6);}int main(){ int T; scanf("%d",&T); while(T--){ double n; scanf("%lf",&n); if(n-6<-eps||cal(100)-n<-eps)///排除不可能的情况,否则超时 { printf("No solution!\n"); continue; } double l=0,r=100; while(r-l>-eps){ double mid=(l+r)/2; double t=cal(mid); if(fabs(t-n)<=eps){ printf("%.4lf\n",mid); break; } else if(t-n<-eps) l=mid; else r=mid; } } return 0;}
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