Swift爬行篇 UISegmentedControl
来源:互联网 发布:宁波行知实验小学好吗 编辑:程序博客网 时间:2024/04/30 05:23
UISegmentedControl
1. 创建
let appsArray:[String] = ["0","1","2","3","4"] let segmented:UISegmentedControl = UISegmentedControl(items: appsArray) segmented.frame = CGRectMake(10, 310, 300, 20) segmented.selectedSegmentIndex = 0 self.view.addSubview(segmented)
segmented.selectedSegmentIndex 设置初始化选择
2.重新修改分段卡的显示内容
let index = segment.selectedSegmentIndex TestLable.text = ("第\(index)个") segment.setTitle(TestLable.text, forSegmentAtIndex: index)
3. 插入图片
segment.setImage(UIImage(named: "green.png"), forSegmentAtIndex: index)
插入图片后标题将会消失,图片和标题有且只能显示一个
4.在原有的标题中再插入一个标题
segment.insertSegmentWithTitle(("第\(index+1)个"), atIndex: index, animated: true)该标题将会插入在index的前面
5.获取分段卡的总数
let count = segment.numberOfSegments
6.获取分段卡的内容和图片
let title = segment.titleForSegmentAtIndex(index)let title = segment.imageForSegmentAtIndex(index)
7.点击后是否自动取消选择
segmented.momentary = truetrue:自动取消选择 false:不自动取消选择,直到下个title被选中为止
8.边框颜色和背景颜色
segmented.tintColor = UIColor.redColor()segmented.layer.backgroundColor = UIColor.orangeColor().CGColor
9.使能标题
segment.setEnabled(false, forSegmentAtIndex: index)
10.设置宽度
segment.setWidth(30.0, forSegmentAtIndex: index)
func removeSegmentAtIndex(segment: Int, animated: Bool) func removeAllSegments()
0 0
- Swift爬行篇 UISegmentedControl
- Swift 爬行篇 UITableView
- Swift爬行篇-- UIButton
- swift爬行篇 滑块,进度条,步进,
- swift UISegmentedControl
- swift UISegmentedControl
- Swift UISegmentedControl(分组控件)
- Swift UIStepper/UISegmentedControl/UIActivityIndicatorView
- Swift 之UISegmentedControl
- iOS开发——UI篇Swift篇&UISegmentedControl
- Swift UITextField,UITextView,UISegmentedControl,UISwitch
- Swift开发IOS-UISegmentedControl
- Swift基础(十八)UISegmentedControl
- Swift开发:Swift 修改UISegmentedControl字体大小,颜色
- UISegmentedControl
- UISegmentedControl
- UISegmentedControl
- UISegmentedControl
- Python随机数生成方法
- C程序存储空间布局(一)——各数据段的内存位置
- 生产者消费者 C++
- 时间改变一切
- div滚动字幕
- Swift爬行篇 UISegmentedControl
- Android 循环滑动viewpager
- LeetCode: Single Number II
- OGRE3D 渲染系统线程化
- VB控件的左对齐和上对齐Sub
- Matlab 2014b For Mac安装破解
- POJ 3259 Wormholes(SPFA算法判断是否存在负环)
- Activity的2种启动方式
- HDU 1304 A Contesting Decision