【LeetCode】(231)Power of Two(Easy)

题目

Power of Two

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Question Solution 

Given an integer, write a function to determine if it is a power of two.

解析

超级简单，每次判断是否能被2除，可以的话就除以2继续循环。考虑负数和1的情况。

class Solution {public:    bool isPowerOfTwo(int n) {        if (n == 1) { return true; } if (n <= 0) { return false; } while (n != 1) { if (n%2 != 0) { return false; } else { n = n/2; } } return true;    }};