POJ1005 I Think I Need a Houseboat
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http://poj.org/problem?id=1005
半夜不睡觉刷题好可怕……刷水题~
题意:洪水每年增长50平方英里,洪水呈半圆形,第一年刚开始时洪水为0平方英里。现给出坐标,求该坐标最早在第几年被洪水淹没(被水淹没 不知所措)。
大水题……我没看题目后面还输出END OF OUTPUT. Wr了一次,仔细读题~
对于一个坐标,我们可以求出它到原点的距离,这就是r,定义π = 3.14,那么半圆的面积就是πr^2,又因为题目是从1开始计算,所以把答案下取整后+1即可。
代码如下:
#include<iostream>#include<cstdio>#include<cstring>#include<cmath>using namespace std;const double pi = 3.14;double ans;double flo = 50.00;int main(){ int t; scanf("%d",&t); for(int i = 1;i <= t;i ++) { double x,y; cin>>x>>y; double r = sqrt(x*x+y*y); ans = (pi*r*r)/2/flo; printf("Property %d: This property will begin eroding in year %d.\n",i,(int)(ans)+1); } cout<<"END OF OUTPUT."; return 0;}
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