Leetcode 235 Lowest Common Ancestor of a Binary Search Tree
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Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______6______ / \ ___2__ ___8__ / \ / \ 0 _4 7 9 / \ 3 5
For example, the lowest common ancestor (LCA) of nodes 2
and 8
is 6
. Another example is LCA of nodes 2
and 4
is 2
, since a node can be a descendant of itself according to the LCA definition.
public class Solution235 { public boolean findPath(TreeNode root, TreeNode p, List<TreeNode> result) { if(root == null) return false; if(root == p) { result.add(root); return true; } if(root.val >= p.val) { result.add(root.left); root = root.left; } else { result.add(root.right); root = root.right; } findPath(root,p,result); return true; } public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) { List<TreeNode> listp = new ArrayList<TreeNode>(); List<TreeNode> listq = new ArrayList<TreeNode>(); listp.add(root); listq.add(root); findPath(root, p, listp); findPath(root, q, listq); TreeNode ans = root; for (int i = 1, j = 1; i < listp.size() && j < listq.size(); i++, j++) { if(listp.get(i).equals(listq.get(j))) { ans = listp.get(i); } else { break; } } return ans; } public static void main(String[] args) { TreeNode p = null, q = null; TreeNode root = new TreeNode(6); root.left = new TreeNode(2); p = root.left; root.right = new TreeNode(8); //q = root.right; root.left.left = new TreeNode(0); root.left.right = new TreeNode(4); q = root.left.right; root.left.right.left = new TreeNode(3); root.left.right.right = new TreeNode(5); root.right.left = new TreeNode(7); root.right.right = new TreeNode(9); TreeNode ans = new Solution235().lowestCommonAncestor(root, p, q); System.out.println(ans.val); }}
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