hdu1029 Ignatius and the Princess IV

Problem Description

"OK, you are not too bad, em... But you can never pass the next test." feng5166 says.

"I will tell you an odd number N, and then N integers. There will be a special integer among them, you have to tell me which integer is the special one after I tell you all the integers." feng5166 says.

"But what is the characteristic of the special integer?" Ignatius asks.

"The integer will appear at least (N+1)/2 times. If you can't find the right integer, I will kill the Princess, and you will be my dinner, too. Hahahaha....." feng5166 says.

Can you find the special integer for Ignatius?

 

Input

The input contains several test cases. Each test case contains two lines. The first line consists of an odd integer N(1<=N<=999999) which indicate the number of the integers feng5166 will tell our hero. The second line contains the N integers. The input is terminated by the end of file.

 

Output

For each test case, you have to output only one line which contains the special number you have found.

 

Sample Input

51 3 2 3 3111 1 1 1 1 5 5 5 5 5 571 1 1 1 1 1 1

 

Sample Output

351

解答：

这道题是次数出现大于等于（n+1)/2的数只有一个吗？直接重新开另一个数组记录就行。累加到这个值后就输出这个数

这道简单题却提交了好多次，runtime error，因为数组开小了，开到（999999+1)/2就可以。可是为什么开到50000也可以过，搞不懂了。

#include <iostream>#include <cstdio>#include <cmath>#include <cstring>using namespace std;int main(){    int n,m;    int a;    int b[500000];    while(scanf("%d",&n)!=EOF)    {        memset(b,0,sizeof(b));        for(int i=0;i<n;i++)        {            scanf("%d",&a);            b[a]++;            if(b[a]>=(n+1)/2)                m=a;        }        printf("%d\n",m);    }    return 0;}