求字符串中数字字符转换成数字之后的总和

#include<iostream>#include<stdio.h>using namespace std;int SumString(char *r){char *p = r;if (p == NULL)return -1;    char *q = p;int sum = 0;while(*p != '\0'){   while(*p > '9'|| *p < '0' && *p != '\0'){p++;q++;}while(*q >= '0'&& *q <= '9')q++;        int su = 0; while(p != q){ su = su *10 + (*p - '0');p++;}sum  = sum + su;p = q;}return sum;}void main(){char *str = "5ab5cb345bj10k~";int m = SumString(str);printf("%d\n",m);}