hdu 2222 AC自动机模板题（指针版+数组版）

Keywords Search

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 44959    Accepted Submission(s): 14215

Problem Description

In the modern time, Search engine came into the life of everybody like Google, Baidu, etc.
Wiskey also wants to bring this feature to his image retrieval system.
Every image have a long description, when users type some keywords to find the image, the system will match the keywords with description of image and show the image which the most keywords be matched.
To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords will be match.

 

Input

First line will contain one integer means how many cases will follow by.
Each case will contain two integers N means the number of keywords and N keywords follow. (N <= 10000)
Each keyword will only contains characters 'a'-'z', and the length will be not longer than 50.
The last line is the description, and the length will be not longer than 1000000.

 

Output

Print how many keywords are contained in the description.

 

Sample Input

15shehesayshrheryasherhs

 

Sample Output

3

 

指针版

#include <iostream>#include <vector>#include <map>#include <set>#include <queue>#include <stack>#include <algorithm>#include <cstdio>#include <string>#include <cstring>#include <cmath>#include <ctime>using namespace std;#pragma comment(linker,"/STACK:102400000,102400000") /// kuo zhan#define clr(s,x) memset(s,x,sizeof(s))#define lson l,m,rt<<1#define rson m+1,r,rt<<1|1#define lowbit(x) (x&(-x))#define PB push_back#define For(i,a,b) for(int i=a;i<b;i++)#define FOR(i,a,b) for(int i=a;i<=b;i++)typedef long long               LL;typedef unsigned int            uint;typedef unsigned long long      ULL;typedef vector<int>             vint;typedef vector<string>          vstring;void RI (int& x){    x = 0;    char c = getchar ();    while (c == ' '||c == '\n')    c = getchar ();    bool flag = 1;    if (c == '-'){        flag = 0;        c = getchar ();    }    while (c >= '0' && c <= '9'){        x = x * 10 + c - '0';        c = getchar ();    }    if (!flag)    x = -x;}void RII (int& x, int& y){RI (x), RI (y);}void RIII (int& x, int& y, int& z){RI (x), RI (y), RI (z);}const double PI  = acos(-1.0);const int maxn   = 1e6 + 100;const int maxm   = 55;const int kind   = 26;const LL mod     = 1e9 + 7;const double eps = 1e-9;const int INF    = 0x7fffffff;/************************************END DEFINE*********************************************/struct node{    int cnt;    node *nxt[kind];    node *fail;};node *q[maxn];char kw[maxm];char s[maxn];int head,tail;node *root;void add_word(char *word,node *root){    int idx,len;    node *p = root,*newnode;    len = strlen(word);    For(i,0,len){        idx = word[i] - 'a';        if(!p->nxt[idx]){            newnode = (struct node *)malloc(sizeof(struct node));            For(j,0,kind)newnode->nxt[j] = 0;            newnode->cnt = 0;            newnode->fail = 0;            p->nxt[idx] = newnode;        }        p = p->nxt[idx];    }    p->cnt++;}void build(node *root){    head = 0,tail = 1;    q[head] = root;    node *tmp,*p;    while(head<tail){        tmp = q[head++];        For(i,0,kind){            if(tmp->nxt[i]){                if(tmp == root)tmp->nxt[i]->fail = root;                else{                    p = tmp->fail;                    while(p){                        if(p->nxt[i]){                            tmp->nxt[i]->fail = p->nxt[i];                            break;                        }                        p = p->fail;                    }                    if(!p)tmp->nxt[i]->fail = root;                }                q[tail++] = tmp->nxt[i];            }        }    }}int query(node *root){    int ct = 0,idx = 0,len = strlen(s);    node *p = root;    For(i,0,len){        idx = s[i]-'a';        while(!p->nxt[idx]&&p!=root)p = p->fail;        p=p->nxt[idx];        if(!p)p=root;        node *tmp = p;        while(tmp!=root){            if(tmp->cnt>=0){                ct+=tmp->cnt;                tmp->cnt=-1;            }            else break;            tmp = tmp->fail;        }    }    return ct;}int main(){    int T;    RI(T);    while(T--){        int n;        RI(n);        node *root = (struct node *)malloc(sizeof(struct node));        For(i,0,kind)root->nxt[i] = 0;        root->fail = 0;        root->cnt = 0;        while(n--){            scanf("%s",kw);            add_word(kw,root);        }        build(root);        scanf("%s",s);        int ans = query(root);        printf("%d\n",ans);    }    return 0;}

数组版#include <iostream>#include <vector>#include <map>#include <set>#include <queue>#include <stack>#include <algorithm>#include <cstdio>#include <string>#include <cstring>#include <cmath>#include <ctime>using namespace std;#pragma comment(linker,"/STACK:102400000,102400000") /// kuo zhan#define clr(s,x) memset(s,x,sizeof(s))#define lson l,m,rt<<1#define rson m+1,r,rt<<1|1#define lowbit(x) (x&(-x))#define PB push_back#define For(i,a,b) for(int i=a;i<b;i++)#define FOR(i,a,b) for(int i=a;i<=b;i++)typedef long long               LL;typedef unsigned int            uint;typedef unsigned long long      ULL;typedef vector<int>             vint;typedef vector<string>          vstring;void RI (int& x){    x = 0;    char c = getchar ();    while (c == ' '||c == '\n')    c = getchar ();    bool flag = 1;    if (c == '-'){        flag = 0;        c = getchar ();    }    while (c >= '0' && c <= '9'){        x = x * 10 + c - '0';        c = getchar ();    }    if (!flag)    x = -x;}void RII (int& x, int& y){RI (x), RI (y);}void RIII (int& x, int& y, int& z){RI (x), RI (y), RI (z);}/************************************END DEFINE*********************************************/const int maxn = 500010;const int kind = 26;int idx(char c){return c-'a';}int chd[maxn][kind],sz,val[maxn],fail[maxn],last[maxn];void init(){    sz=1;    memset(chd[0],0,sizeof(chd[0]));    memset(val,0,sizeof(val));    memset(fail,0,sizeof(fail));    memset(last,0,sizeof(last));}void add(char *p){    int u=0;    int len = strlen(p);    for(int i=0;i<len;i++){        int c = idx(p[i]);        if(chd[u][c]==0){            memset(chd[sz],0,sizeof(chd[sz]));            chd[u][c]=sz++;        }        u=chd[u][c];    }    val[u]++;}int getFail(){    queue<int> q;    fail[0]=0;    for(int c=0;c<kind;c++){        int u=chd[0][c];        if(u){            fail[u]=0;q.push(u);last[u]=0;        }    }    while(!q.empty()){        int r=q.front(); q.pop();        for(int c=0;c<kind;c++){            int u=chd[r][c];            if(!u){                chd[r][c]=chd[fail[r]][c];                continue;            }            q.push(u);            int v=fail[r];            while(v&&!chd[v][c]) v=fail[v];            fail[u]=chd[v][c];            last[u]=(val[fail[u]])?fail[u]:last[fail[u]];        }    }}int query(char *T){    int len = strlen(T), j = 0,ans = 0;    for(int i = 0; i < len; i++){        int c = idx(T[i]);        while(j && chd[j][c]==0) j = fail[j];        j = chd[j][c];        int temp = j;        while(temp && val[temp]){            ans+=val[temp];            val[temp]=0;            temp = fail[temp];        }    }    return ans;}char t[55];char s[1000005];int main(){    int T;    RI(T);    while(T--){        int n;        RI(n);        init();        while(n--){            scanf("%s",t);            add(t);        }        getFail();        scanf("%s",s);        printf("%d\n",query(s));    }    return 0;}