[c] poj1008

http://poj.org/problem?id=1008

先把距第一天的时间算出来，再算用另一个计法算出日子就好了，是用取余和整除做的题

#include<iostream>#include<stdio.h>#include<string>using namespace std;string a1[19]={"pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin", "mol", "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu", "uayet"};string a2[20]={"imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik", "lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", "eznab", "canac", "ahau"};int main(){int n;cin>>n;cout<<n<<endl;for(int i=0;i<n;i++){int x;cin>>x;string a;cin>>a;cin>>a;int y;cin>>y;int day;int m;for(int j=0;j<20;j++){if(a==a1[j]){m=j;break;}}day=x+m*20+y*365;int ry=day/260;int rm=day%260%20;int rd=day%13+1;cout<<rd<<' '<<a2[rm]<<' '<<ry<<endl;}return 0;}