数据结构与算法分析Java版练习1.3

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package ch01;/** * 练习1.3 只使用处理I/O的printDigit方法，编写一种方法以输出任意 *         double型量(可以是负数）。 */public class EX03 {private static void printDigit(int i) {System.out.print(i);}private static void printOut(int n) {if (n >= 10) {printOut(n/10);}printDigit(n%10);}private static void printDouble(double f) {//首先找出负号if (f < 0) {System.out.print('-');f = -f;}//找出小数点位置String value = String.valueOf(f);int intPart = 0, dotPart = 0;int dotPos = value.indexOf('.');if (dotPos < 0) {intPart = Integer.valueOf(value);printOut(intPart);} else if (dotPos == 0) {intPart = 0;dotPart = Integer.valueOf(value.substring(dotPos+1));printOut(intPart);System.out.print('.');printOut(dotPart);} else {intPart = Integer.valueOf(value.substring(0, dotPos));dotPart = Integer.valueOf(value.substring(dotPos + 1));printOut(intPart);System.out.print('.');printOut(dotPart);} System.out.println();}public static void main(String[] args) {printDouble(10.234);printDouble(-10000.2);printDouble(1000);printDouble(10001.0);printDouble(10001.1456);}}

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