1004 Let the Balloon Rise
来源:互联网 发布:青铜卡尺 知乎 编辑:程序博客网 时间:2024/06/06 00:25
Problem Description
Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.
This year, they decide to leave this lovely job to you.
This year, they decide to leave this lovely job to you.
Input
Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.
A test case with N = 0 terminates the input and this test case is not to be processed.
A test case with N = 0 terminates the input and this test case is not to be processed.
Output
For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.
Sample Input
5greenredblueredred3pinkorangepink0
Sample Output
redpink
Author
WU, Jiazhi
Source
ZJCPC2004
则最后count最大的颜色就是最popular的颜色。
#include<iostream>#include<string>using namespace std;int main(){int N,i,j,count,max,color;char a[1001][16];while(cin>>N&&N!=0){getchar();max=1;for(i=0;i<N;i++){gets(a[i]);}for(i=0;i<N;i++){count=1;if(a[i][0]=='\0')continue;for(j=i+1;j<N;j++){if(a[j][0]=='\0')continue;if(strcmp(a[i],a[j])==0){count++;a[j][0]='\0';}}if(count>max){max=count;color=i;}}puts(a[color]);}}
0 0
- 1004 Let the Balloon Rise
- 1004 Let the Balloon Rise
- 1004 Let the Balloon Rise
- 1004let the balloon rise
- Let the Balloon Rise 1004
- 1004 Let the Balloon Rise
- Let the Balloon Rise(1004)
- 1004Let the Balloon Rise
- Let the Balloon Rise(1004)
- Let the Balloon Rise(1004)
- 1004:Let the Balloon Rise
- 1004 let the balloon rise
- 1004 Let the Balloon Rise
- 1004 Let the Balloon Rise
- 1004-Let the Balloon Rise
- 1004 Let the Balloon Rise
- 1004 Let the Balloon Rise
- 1004 Let the Balloon Rise
- Android JNI打印Log
- Sql 调优 与 OLPT
- spring 拦截器(ProxyFactoryBean,BeanNameAutoProxyCreator)
- iOS-数据持久化(一)
- 【软工6】软件开发小组
- 1004 Let the Balloon Rise
- n皇后 dfs解法
- 操作系统开发之——最简单的Bootsect(可直接在里面加代码)
- codeforces 27E E. Number With The Given Amount Of Divisors(dp+数论)
- [POJ 2236]Wireless Network[并查集]
- 西方人眼中的中国的不同:文明国家、民族的概念 和 国家的属性以及它和社会的关系
- Ubuntu14.04安装后vim不可用的问题
- 网页前端的相关技术整理
- 线程之间的通信-(子线程获得主线程的方式)