将字符串中的标点符号过滤掉

来源：互联网发布：天津幼儿园软件编辑：程序博客网时间：2024/06/05 12:07

开发中我们有可能会遇到这种情况，就是将字符串中的某个字符去掉

@Testpublic void test() {String d = trimPunctuation2("你，好oewefo,21.2!;:、1?dsf");System.out.println(d);}// 将字符串中的标点符号过滤掉public static String trimPunctuation2(String str) {String punct[] = { ",", ".", "!", "?", ";", ":", "，", "。", "！", "？","；", "：", "、" };List<String> punctList = Arrays.asList(punct); // 将String数组转List集合StringBuilder result = new StringBuilder();for (int i = 0; i < str.length(); i++) {Character c = str.charAt(i);if (punctList.contains(c.toString())) {} else {result.append(str.charAt(i));}}return result.toString();}// 将字符串中的标点符号过滤掉public static String trimPunctuation(String str) {StringBuilder result = new StringBuilder();for (int i = 0; i < str.length(); ++i) {char punct[] = { ',', '.', '!', '?', ';', ':', '，', '。', '！', '？','；', '：', '、' };boolean need_filter = false;for (int j = 0; j < punct.length; ++j) {if (punct[j] == str.charAt(i)) {need_filter = true;break;}}if (!need_filter) {result.append(str.charAt(i));}}return result.toString();}

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