1219：AC Me

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1219

方法：哈希表

思路：又是一道大水题，按照哈希表统计各个字母出现的次数，小case，主要是要看清格式，为了个格式PE了两次，郁闷......

难点：无

#include <cstdio>#include <string.h>using namespace std;char letter[26] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};int main(){int len;char str[100000];while(gets(str)){int book[26] = {0};len = strlen(str);for(int i = 0;i < len;i++){if(str[i]>='a'&&str[i]<='z'){book[str[i]-'a']++;}}for(int i = 0;i < 26;i++){if(i!=25)printf("%c:%d\n",letter[i],book[i]);else printf("%c:%d\n",letter[i],book[i]);}printf("\n");}return 0;}