[leetcode] 20.Valid Parentheses
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题目:
Given a string containing just the characters ‘(‘, ‘)’, ‘{‘, ‘}’, ‘[’ and ‘]’, determine if the input string is valid.
The brackets must close in the correct order, “()” and “()[]{}” are all valid but “(]” and “([)]” are not.
题意:
给定一个字符串,里面包含了’(‘, ‘)’, ‘{‘, ‘}’, ‘[’ , ‘]’。查看这个字符串是否是合法的。像这就是合法的,[(])就是不合法的。
思路:
使用栈存放符号,遇到左括号就入栈,遇到右括号就查看是否与栈顶的左括号相匹配。
代码如下:
class Solution {public: bool isValid(string s) { if(s.empty())return true; stack<char> signs; for(auto c : s) { switch(c) { case '(':signs.push(c);break; case '[':signs.push(c);break; case '{':signs.push(c);break; case ')':{ if(signs.empty() || signs.top() != '(')return false; signs.pop(); break; } case ']':{ if(signs.empty() || signs.top() != '[')return false; signs.pop(); break; } case '}':{ if(signs.empty() || signs.top() != '{')return false; signs.pop(); break; } } } return signs.empty(); }};
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