[Leetcode]#7 Reverse Integer
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//#7 Reverse Integer//8ms 100%class Solution {public: int reverse(int x) { if(x == -2147483648) return 0; bool positive(true); if(x < 0) { positive = false; x = abs(x); } int result(0); while(x != 0) { if(result >= 214748365 || (result == 214748364 && x >= 8)) { //cout << "result: " << result << ", x%10: " << x%10 << " overflow\n"; return 0; } result = result*10 + x%10; x = x / 10; } if(!positive) result = result * -1; return result; }};
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