leetcode 9: Palindrome Number
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Reverse the number and compare it with the original one.
class Solution {public: bool isPalindrome(int x) { int old_x=x; int new_x=0; while(x>0) { if((INT_MAX-x%10)/10<new_x) return false; new_x=new_x*10+x%10; x/=10; } return new_x==old_x; }};
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