【Leetcode】Construct binary tree from inorder and postorder traversal

【题目】

Given inorder and postorder traversal of a tree, construct the binary tree.

Note:
You may assume that duplicates do not exist in the tree.

【思路】

pretty similar with that of 

【代码】

public TreeNode buildTree(int[] inorder, int[] postorder) {        if(inorder.length == 0 || inorder.length != postorder.length) return null;        return buildTree(inorder,postorder,0,inorder.length-1,0,postorder.length-1);    }    public TreeNode buildTree(int[] inorder, int[]postorder, int ilow, int ihigh, int plow, int phigh) {         TreeNode root = new TreeNode(postorder[phigh]);         int i=-1;         for(i = ilow; i <= ihigh; i++) {               if(root.val == inorder[i]) {                     break;                  }             }          if(i != ilow) root.left = buildTree(inorder, postorder, ilow, i-1, plow,plow+i-ilow-1);          if(i != ihigh) root.right = buildTree(inorder,postorder, i+1, ihigh, plow+i-ilow, phigh-1);          return root;    }