1039. Course List for Student (25)
来源:互联网 发布:ubuntu 16.04 uuidgen 编辑:程序博客网 时间:2024/05/29 19:52
1039. Course List for Student (25)
Zhejiang University has 40000 students and provides 2500 courses. Now given the student name lists of all the courses, you are supposed to output the registered course list for each student who comes for a query.
Input Specification:
Each input file contains one test case. For each case, the first line contains 2 positive integers: N (<=40000), the number of students who look for their course lists, and K (<=2500), the total number of courses. Then the student name lists are given for the courses (numbered from 1 to K) in the following format: for each course i, first the course index i and the number of registered students Ni (<= 200) are given in a line. Then in the next line, Ni student names are given. A student name consists of 3 capital English letters plus a one-digit number. Finally the last line contains the N names of students who come for a query. All the names and numbers in a line are separated by a space.
Output Specification:
For each test case, print your results in N lines. Each line corresponds to one student, in the following format: first print the student's name, then the total number of registered courses of that student, and finally the indices of the courses in increasing order. The query results must be printed in the same order as input. All the data in a line must be separated by a space, with no extra space at the end of the line.
Sample Input:11 54 7BOB5 DON2 FRA8 JAY9 KAT3 LOR6 ZOE11 4ANN0 BOB5 JAY9 LOR62 7ANN0 BOB5 FRA8 JAY9 JOE4 KAT3 LOR63 1BOB55 9AMY7 ANN0 BOB5 DON2 FRA8 JAY9 KAT3 LOR6 ZOE1ZOE1 ANN0 BOB5 JOE4 JAY9 FRA8 DON2 AMY7 KAT3 LOR6 NON9Sample Output:
ZOE1 2 4 5ANN0 3 1 2 5BOB5 5 1 2 3 4 5JOE4 1 2JAY9 4 1 2 4 5FRA8 3 2 4 5DON2 2 4 5AMY7 1 5KAT3 3 2 4 5LOR6 4 1 2 4 5NON9 0
# include <iostream># include <string># include <map># include <vector># include <cstdio># include <algorithm>using namespace std;char temp[6];int str2int(char *str){ int key = str[3] - '0'; for (int i=2;i>=0;i--) key = str[i] - 'A' + 26*key; return key;}vector<int> stu_course[26*26*26*26];int main(){ int i,j,k; int n,m; scanf("%d%d",&n,&m); while (m--) { cin >> j >> k; while (k--) { scanf("%s",temp); stu_course[str2int(temp)].push_back(j); } } while (n--) { scanf("%s",temp); vector<int>& loc = stu_course[str2int(temp)]; int size = loc.size(); sort(loc.begin(),loc.end()); cout << temp << ' ' << size; for (i=0;i<size;i++) printf(" %d",loc[i]); printf("\n"); } return 0;}
- 1039. Course List for Student (25)
- 1039. Course List for Student (25)-PAT
- 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- PAT 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- PAT 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- PAT 1039. Course List for Student (25)
- 1039. Course List for Student (25)
- PAT 1039. Course List for Student (25)
- 软件设计师中的前缀、中缀和后缀表达式
- jQuery 选项卡插件 FengTab by FungLeo
- 一张图看懂block使用不当造成内存泄露
- XML解析之Dom4j解析
- 一些学习编程的站点
- 1039. Course List for Student (25)
- 自学QT之堆栈窗口
- eclipse中tomcat正常启动后,浏览器就访问不了tomcat首页——问题解决
- 浅谈GCD
- Application应用共享数据
- Android基本控件RadioGroup和RadioButton学习
- matlab BPSK调制方式代码实现
- java-8大基本类型
- HDU 4288 Coder(vector + upper_bound, lower_bound)