字符串处理小结

来源:互联网 发布:大数据医疗行业的应用 编辑:程序博客网 时间:2024/06/06 10:07

字符串拷贝


字符串格式化

_tprintf只是输出到Console窗口,如:

[cpp] view plaincopy
  1. double num1, num2;  
  2. _tprintf(_T("%lf / %lf = ?\n"),num1,num2);  
_stprintf是输出到指定的字符串变量,如:

[cpp] view plaincop
  1. TCHAR title[50];  
  2. _stprintf(title,_T("标题"));  
  3. TCHAR command[50];  
  4. _stprintf(command,_T("%s %lf / %lf"),_T("两个数为:"),num1,num2);  

从字符串获取输入

_stscanf( _strTemp, _T("%d,%d,%d,%d,%d,%d"),  &i,&j,&k,&l,&m,&n );


字符串分割

// crt_strtok.c/* In this program, a loop uses strtok * to print all the tokens (separated by commas * or blanks) in the string named "string". */#include <string.h>#include <stdio.h>char string[] = "A string\tof ,,tokens\nand some  more tokens";char seps[]   = " ,\t\n";char *token;int main( void ){   printf( "Tokens:\n" );   /* Establish string and get the first token: */   token = strtok( string, seps );   while( token != NULL )   {      /* While there are tokens in "string" */      printf( " %s\n", token );      /* Get next token: */      token = strtok( NULL, seps );   }}

Output

Tokens: A string of tokens and some more tokens


The strtok() function returns a pointer to the next "token" in str1, where str2 contains the delimiters that determine the token. strtok() returns NULL if no token is found. In order to convert a string to tokens, the first call to strtok() should have str1 point to the string to be tokenized. All calls after this should have str1 beNULL.

For example:
char str[] = "now # is the time for all # good men to come to the # aid of their country";
char delims[] = "#";
char *result = NULL;
result = strtok( str, delims );
while( result != NULL ) {
printf( "result is \"%s\"\n", result );
    result = strtok( NULL, delims );

    

The above code will display the following output:
result is "now "
result is " is the time for all "
result is " good men to come to the "
result is " aid of their country"



0 0
原创粉丝点击