codeforces 21A Jabber ID

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Jabber ID on the national Berland service «Babber» has a form <username>@<hostname>[/resource], where

<username> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of<username> is between 1 and 16, inclusive.
<hostname> — is a sequence of word separated by periods (characters «.»), where each word should contain only characters allowed for<username>, the length of each word is between 1 and 16, inclusive. The length of<hostname> is between 1 and 32, inclusive.
<resource> — is a sequence of Latin letters (lowercase or uppercase), digits or underscores characters «_», the length of<resource> is between 1 and 16, inclusive.

The content of square brackets is optional — it can be present or can be absent.

There are the samples of correct Jabber IDs: mike@codeforces.com,007@en.codeforces.com/contest.

Your task is to write program which checks if given string is a correct Jabber ID.

Input

The input contains of a single line. The line has the length between 1 and 100 characters, inclusive. Each characters has ASCII-code between 33 and 127, inclusive.

Output

Print YES or NO.

Sample test(s)

Input

mike@codeforces.com

Output

YES

Input

john.smith@codeforces.ru/contest.icpc/12

Output

NO

细心，再细心一点！！！！！

 #include<iostream> using namespace std; #include<string.h> int main() {      char s[150];      int i,k,k1,a[200],s8,j,s1,s2,s3,s4,s5,s6,s7;      while(cin>>s)      {k=-1,k1=-1;      for(i=0;i<strlen(s);i++)          if(s[i]=='@')k=i;      if(k==-1||k==strlen(s)-1)cout<<"NO\n";//判断是否有@或@为最后一位      else      { if(k<1||k>16)s8=0;        else s8=1;//判断<username>的大小是否为1~16；          for(i=k;i<strlen(s);i++)          if(s[i]=='/'){k1=i;break;}          for(i=0;i<k;i++)            if(s[i]>='0'&&s[i]<='9'||s[i]>='A'&&s[i]<='Z'||s[i]>='a'&&s[i]<='z'||s[i]=='_')                s1=1;                else  {s1=0;break;}//判断<username>的字符是否正确；            if(k1==-1)//判断@后面是否存在‘/’；            {                if(strlen(s)-k-1>32)                   s4=0;                   else s4=1;//判断<hostname>的大小是否为1~32；                     j=0;s2=1;                    for(i=k;i<strlen(s);i++)                        if(s[i]=='.'||s[i]==0||s[i]=='@')                           a[j++]=i;                     for(i=0;i<j-1;i++)                     if(a[i+1]-a[i]-1<1||a[i+1]-a[i]-1>16)                           s2=0;//判断每两个‘.’之间的字符串大小是否为1~16；                    for(i=k+1;i<strlen(s);i++)                         if(s[i]!='.')                         if(s[i]>='0'&&s[i]<='9'||s[i]>='A'&&s[i]<='Z'||s[i]>='a'&&s[i]<='z'||s[i]=='_')                              s3=1;                            else  {s3=0;break;}//判断<hostname>的字符是否正确；                           s7=1;                      for(i=k;i<strlen(s);i++)                    if(s[i]=='.')                        { if(s[i+1]>='0'&&s[i+1]<='9'||s[i+1]>='A'&&s[i+1]<='Z'||s[i+1]>='a'&&s[i+1]<='z'||s[i+1]=='_')                               s7=1;                            else {s7=0; break;}                        }//判断‘.’后面是否有字符，若无‘.’，则也s7=1;                       // cout<<s1<<" "<<s2<<" "<<s3<<" "<<s4<<" "<<s7<<" "<<s8<<endl;                    if(s1&&s2&&s3&&s4&&s7&&s8)cout<<"YES\n";                    else cout<<"NO\n";            }            else            { int f;               if(k1-k-1>32)                   s4=0;                   else s4=1;//判断<hostname>的大小是否为1~32；                j=0;s2=1;               s7=1;                for(i=k;i<k1;i++)                    if(s[i]=='.')                        { if(s[i+1]>='0'&&s[i+1]<='9'||s[i+1]>='A'&&s[i+1]<='Z'||s[i+1]>='a'&&s[i+1]<='z'||s[i+1]=='_')                               s7=1;                               else {s7=0; break;}                        }//判断‘.’后面是否有字符，若无‘.’，则也s7=1;                    for(i=k;i<k1;i++)                   if(s[i]=='.'||s[i]==0||s[i]=='@')                            a[j++]=i;                     for(i=0;i<j-1;i++)                     if(a[i+1]-a[i]-1<1||a[i+1]-a[i]-1>16)                         s2=0;//判断每两个‘.’之间的字符串大小是否为1~16；                    for(i=k+1;i<k1;i++)                         if(s[i]!='.')                         if(s[i]>='0'&&s[i]<='9'||s[i]>='A'&&s[i]<='Z'||s[i]>='a'&&s[i]<='z'||s[i]=='_')                              s3=1;                            else  {s3=0;break;}//判断<hostname>的字符是否正确；                            if(strlen(s)-k1-1<1||strlen(s)-k1-1>16)s5=0;                            else s5=1;//判断<resource>的大小是否为1~16；                            for(i=k1+1;i<strlen(s);i++)                                 if(s[i]>='0'&&s[i]<='9'||s[i]>='A'&&s[i]<='Z'||s[i]>='a'&&s[i]<='z'||s[i]=='_')                              s6=1;                            else  {s6=0;break;}//判断<resource>的字符是否正确；                           // cout<<s1<<" "<<s2<<" "<<s3<<" "<<s4<<" "<<s5<<" "<<s6<<" "<<s7<<" "<<s8<<endl;                            if(s8&&s1&&s2&&s3&&s4&&s5&&s6&&s7)                                cout<<"YES\n";                           else cout<<"NO\n";            }      }      }     return 0; }

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