笔试题：cvte第一题二分法求字符串

#include <iostream>using namespace std;typedef struct String2Number{    char *String;    int code;};String2Number auString2Number[] = {    {"au",0x10},    {"bc",0x2},    {"chn",0x11},    {"dd",0x3},    {NULL,0},    {"zai",0x80}};bool IsEq(char *str1,char *str2){    char *p1 = str1;    char *p2 = str2;    while (*p1 == *p2 && *p1!='\0')    {        p1++;        p2++;    }    if (*p1 == '\0' && *p2 == '\0')return 0;    if (*p1 > *p2)return 1;    if (*p1 < *p2)return -1;}int GetCode(char *string){    int i = 0;    int j = sizeof(auString2Number) / sizeof(String2Number)-1;//统计元素个数。    while (i <= j)    {        int mid = i + (j - i) / 2;        if (IsEq(auString2Number[mid].String, string)==1)        {            j = mid - 1;        }        else if (IsEq(auString2Number[mid].String, string) == -1)        {            i = mid + 1;        }        else        {            return auString2Number[mid].code;        }    }    return -1;}int main(){    cout << GetCode("au") << endl;    return 0;}