jquery js ajax 不错的想法

<scriptlanguage="JavaScript"> $(document).ready(function(){ $('#YOUR_FORM').submit(function(){// catch the form's submit event $.ajax({// create an AJAX call... data: $(this).serialize(),// get the form data type: $(this).attr('method'),// GET or POST url: $(this).attr('action'),// the file to call success:function(response){// on success.. $('#DIV_CONTAINING_FORM).html(response);// update the DIV}});returnfalse;});});</script>

EDIT

As pointed out in the comments sometimes the above won't work. So try the following:

<scripttype="text/javascript">var frm = $('#FORM-ID');    frm.submit(function(){        $.ajax({            type: frm.attr('method'),            url: frm.attr('action'),            data: frm.serialize(),            success:function(data){                $("#SOME-DIV").html(data);},            error:function(data){                $("#MESSAGE-DIV").html("Something went wrong!");}});returnfalse;});</script>