leetcode #3 Longest Substring Without Repeating Characters
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这题卡了很久才做出来。
主要问题在于当输入与hashmap中已有的数据相同的字母时,还要判断重复是不是发生在目前的length范围内。
如String abcbca
当最后一个a进入时,当前的length范围是“bc”,不过不加以处理,程序会误以为当前hashmap中的a是一个重复进而i-measure.get(s.charAt(i))=5-0=5
而实际上之前的a已经第二个b输入时就已经被排出length范围了,不应该计算在内。
Update:
其实value就是每个字母在数组中最后出现的位置
public class Solution { public int lengthOfLongestSubstring(String s) { int length=0,max=0,i; if(s.length()==1)return 1; char[] input = s.toCharArray(); Map<Character, Integer> measure = new HashMap<Character, Integer>(); for(i=0;i<input.length;i++){ if(measure.containsKey(input[i])&&(i-measure.get(input[i]))<=length){ length=i-measure.get(input[i]); } else length++; measure.put(input[i], i); max=Math.max(max, length); } return max=Math.max(max, length); }}
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