Tenth Line

How would you print just the 10th line of a file?

For example, assume that file.txt has the following content:

Line 1Line 2Line 3Line 4Line 5Line 6Line 7Line 8Line 9Line 10

Your script should output the tenth line, which is:

Line 10

Hint:

1. If the file contains less than 10 lines, what should you output?

2. There's at least three different solutions. Try to explore all possibilities.

题目大意：

输出一个文件的第10行。

思考：

1. 如果文件包含内容不足10行，应该输出什么？

2. 有至少3种不同的解决方法，尝试列举所有的可能方案

Bash脚本：

解法一，使用awk

# Read from the file file.txt and output the tenth line to stdout.awk 'NR == 10' file.txt
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解法二，使用sed

# Read from the file file.txt and output the tenth line to stdout.sed -n '10p' file.txt
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解法三，组合使用tail与head

# Read from the file file.txt and output the tenth line to stdout.tail -n+10 file.txt | head -n1