sqlserver的树形查询

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SQL Server没有ORACLE那样专门的树形查询语法，而这却是很多数据库模型中要用到的，比如主机结构，产品分类等。我查询了很多资料没有一个满意的，基本有3中方案：
1. 简单的带with的递归查询，无法排序，更加无法显示体系架构
2 使用ROW_NUMBER()over功能，比较完美，但某些极端情况不能工作，复杂难懂
3 老外有存储过程来实现，很完美，但建立新的对象很不爽

我综合了各种方法，这是第4中方法，应该很完美了：

WITH tree
AS
(
SELECT ParentAssetID, AssetID,1 AS x2level,nodename,
CAST(nodename AS NVARCHAR(max)) x2name,
CAST(+AssetID AS NVARCHAR(max)) x2id
FROM dbo.Assets
WHERE ParentAssetID IS null
UNION ALL
SELECT c.ParentAssetID, c.AssetID, tree.x2level + 1,c.nodename,
CAST(REPLICATE('-', x2level * 4) + c.nodename AS NVARCHAR(max)) x2name,
tree.x2id +':|:'+ CAST(c.AssetID AS NVARCHAR(max)) x2id
FROM dbo.Assets c
INNER JOIN tree
ON c.ParentAssetID = tree.AssetID
)
SELECT x2name, AssetID, ParentAssetID FROM tree
ORDER BY x2id;

---President
------Vice President
---------CEO
---------CTO
------------Group Project Manager
---------------Project Manager 1
------------------Team Leader 1
---------------------Software Engineer 1
---------------------Software Engineer 2
------------------Test Lead 1
---------------------Tester 1
---------------------Tester 2
---------------Project Manager 2
------------------Team Leader 2
---------------------Software Engineer 3
---------------------Software Engineer 4
------------------Test Lead 2
---------------------Tester 3
---------------------Tester 4
---------------------Tester 5

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