HDU 2133 模拟

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What day is it

Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4419 Accepted Submission(s): 1294

Problem Description

Today is Saturday, 17th Nov,2007. Now, if i tell you a date, can you tell me what day it is ?

Input

There are multiply cases.
One line is one case.
There are three integers, year(0<year<10000), month(0<=month<13), day(0<=day<32).

Output

Output one line.
if the date is illegal, you should output "illegal". Or, you should output what day it is.

Sample Input

2007 11 17

Sample Output

Saturday
#include<cstdio>#include<iostream>using namespace std;int ok(int  n){    if((n%4==0&&n%100!=0)||(n%400==0))        return 1;    return  0;}int main(){int y=0,m=0,d=0;int tian[2][31]= {{0,31,28,31,30,31,30,31,31,30,31,30,31},{0,31,29,31,30,31,30,31,31,30,31,30,31}};    char rr[8][30]= {{"Sunday"},{"Monday"},{"Tuesday"},{"Wednesday"},{"Thursday"},{"Friday"},{"Saturday"}};while(scanf("%d%d%d",&y,&m,&d)!=EOF){if((ok(y)==0&&m==2&&d==29)||m>12||d>tian[ok(y)][m]||m==0||d==0||y==0)        {            printf("illegal\n");            continue;        }       int sum=0;       for(int i=1;i<y;i++)       {       if(ok(i))        sum+=366;       else        sum+=365;       sum%=7;   }   for(int i=1;i<m;i++)   {      sum+=tian[ok(y)][i];            sum%=7;   }   sum+=d;   sum%=7;   printf("%s\n",rr[sum]);}return 0;}

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