Aoj 2450 Do use segment tree【树链剖分】
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树链剖分,个人因为姿势太丑就不发代码了。
维护四个域。
区间和,右端最大连续值,左端最大连续值,答案。
注意的是,2操作是一个有序的操作,因此需要求一个LCA,从某点更新到LCA,再从LCA更新到另一个点。当然也有不要LCA的方法,就是通过判断深度,不swap,直接旋转地找。
// whn6325689// Mr.Phoebe// http://blog.csdn.net/u013007900#include <algorithm>#include <iostream>#include <iomanip>#include <cstring>#include <climits>#include <complex>#include <fstream>#include <cassert>#include <cstdio>#include <bitset>#include <vector>#include <deque>#include <queue>#include <stack>#include <ctime>#include <set>#include <map>#include <cmath>#include <functional>#include <numeric>#pragma comment(linker, "/STACK:1024000000,1024000000")using namespace std;#define eps 1e-9#define PI acos(-1.0)#define INF 0x3f3f3f3f#define LLINF 1LL<<62#define speed std::ios::sync_with_stdio(false);typedef long long ll;typedef unsigned long long ull;typedef long double ld;typedef pair<ll, ll> pll;typedef complex<ld> point;typedef pair<int, int> pii;typedef pair<pii, int> piii;typedef vector<int> vi;#define CLR(x,y) memset(x,y,sizeof(x))#define CPY(x,y) memcpy(x,y,sizeof(x))#define clr(a,x,size) memset(a,x,sizeof(a[0])*(size))#define cpy(a,x,size) memcpy(a,x,sizeof(a[0])*(size))#define debug(a) cout << #a" = " << (a) << endl;#define debugarry(a, n) for (int i = 0; i<(n); i++) { cout << #a"[" << i << "] = " << (a)[i] << endl; }#define mp(x,y) make_pair(x,y)#define pb(x) push_back(x)#define lowbit(x) (x&(-x))#define MID(x,y) (x+((y-x)>>1))#define getidx(l,r) (l+r | l!=r)#define ls getidx(l,mid)#define rs getidx(mid+1,r)#define lson l,mid#define rson mid+1,rtemplate<class T>inline bool read(T &n){ T x = 0, tmp = 1; char c = getchar(); while((c<'0' || c > '9') && c != '-' && c != EOF) c = getchar(); if(c == EOF) return false; if(c == '-') c = getchar(), tmp = -1; while(c >= '0' && c <= '9') x *= 10, x += (c - '0'),c = getchar(); n = x*tmp; return true;}template <class T>inline void write(T n){ if(n<0) { putchar('-'); n = -n; } int len = 0,data[20]; while(n) { data[len++] = n%10; n /= 10; } if(!len) data[len++] = 0; while(len--) putchar(data[len]+48);}//-----------------------------------const int MAXN = 200020;struct Node{ ll sumv, suml, sumr, maxv; ll sett; Node() { sumv = 0; sett = INF; suml = sumr = maxv = -INF; } void setv(ll x, ll num) { sett = x; sumv = x*num; if(x >= 0) suml = sumr = maxv = sumv; else suml = sumr = maxv = x; } Node operator + (const Node &rhs) const { Node c; c.sett = INF; c.sumv = sumv + rhs.sumv; c.suml = max(suml, sumv+rhs.suml); c.sumr = max(sumr+rhs.sumv, rhs.sumr); c.maxv = max(maxv, rhs.maxv); c.maxv = max(c.maxv, sumr+rhs.suml); return c; }} p[MAXN<<1];vector<int> G[MAXN];int num[MAXN], top[MAXN], dep[MAXN];int dfn[MAXN], b[MAXN], fa[MAXN], dfs_clock;int que[MAXN], iii[MAXN], a[MAXN];int n, q, ql, qr, _v;void gao(){ int ft = 0, rear = 0; que[rear++] = 1; fa[1] = 0; dep[1] = 1; while(ft < rear) { int u = que[ft++]; for(int i = 0; i < G[u].size(); i++) { int v = G[u][i]; if(v == fa[u]) continue; fa[v] = u; que[rear++] = v; dep[v] = dep[u]+1; } } memset(num, 0, sizeof num); for(int i = n-1; i >= 0; i--) { int u = que[i]; num[u]++; num[fa[u]] += num[u]; } for(int i = 1; i <= n; i++) { for(int j = 1; j < G[i].size(); j++) if(G[i][j] != fa[i]) if(G[i][0] == fa[i] || num[G[i][j]] > num[G[i][0]]) swap(G[i][0], G[i][j]); } top[1] = 1; for(int i = 1; i < n; i++) { int u = que[i]; if(G[fa[u]][0] == u) top[u] = top[fa[u]]; else top[u] = u; } memset(iii, 0, sizeof iii); ft = 0; dfs_clock = 0; que[++ft] = 1; dfn[1] = ++dfs_clock; b[1] = a[1]; while(ft) { int u = que[ft]; if(iii[u] >= G[u].size()) ft--; else if(G[u][iii[u]] == fa[u]) iii[u]++; else { int v = G[u][iii[u]]; que[++ft] = v; dfn[v] = ++dfs_clock; b[dfn[v]] = a[v]; iii[u]++; } }}void print(int a[]){ for(int i = 1; i <= n; i++) printf("%d ", a[i]); puts("");}void test(){ print(fa); print(top); print(dep); print(dfn); print(b); print(num);}void build(int l, int r){ int idx=getidx(l,r),mid=MID(l,r); p[idx].sett=INF; if(l==r) { p[idx].setv(b[l], 1); return; } build(lson); build(rson); p[idx]=p[ls]+p[rs];}void push_down(int l, int r){ int idx=getidx(l,r),mid=MID(l,r); if(p[idx].sett!=INF) { p[ls].setv(p[idx].sett,mid-l+1); p[rs].setv(p[idx].sett,r-mid); p[idx].sett=INF; }}void update(int l,int r,int L,int R){ int idx=getidx(l,r),mid=MID(l,r); if(L<=l && r<=R) { p[idx].setv(_v, r-l+1); return; } push_down(l,r); if(L<=mid) update(lson,L,R); if(R>mid) update(rson,L,R); p[idx]=p[ls]+p[rs];}Node query(int l, int r,int L,int R){ int idx=getidx(l,r),mid=MID(l,r); if(L==l && r==R) return p[idx]; push_down(l,r); if(R<=mid) return query(lson,L,R); if(L>mid) return query(rson,L,R); return query(lson,L,mid)+query(rson,mid+1,R);}int lca(int u, int v){ while(top[u] != top[v]) { if(dep[top[u]] < dep[top[v]]) swap(u, v); u=fa[top[u]]; } return dep[u] > dep[v] ? v : u;}void change(int u, int v, int c){ int t=lca(u, v); _v=c; while(top[u] != top[t]) { update(1,n,dfn[top[u]],dfn[u]); u=fa[top[u]]; } update(1,n,dfn[t],dfn[u]); while(top[v] != top[t]) { update(1,n,dfn[top[v]],dfn[v]); v=fa[top[v]]; } if(v != t) update(1,n,dfn[t]+1,dfn[v]);}ll outputquery(int u, int v){ if(dfn[u] > dfn[v]) swap(u, v); int t=lca(u, v); if(t==u) swap(u, v); Node L,R; while(top[u] != top[t]) { L=query(1,n,dfn[top[u]],dfn[u])+L; u=fa[top[u]]; } L=query(1,n,dfn[t],dfn[u])+L; while(top[v] != top[t]) { R=query(1,n,dfn[top[v]],dfn[v])+R; v=fa[top[v]]; } if(v!=t) R=R+query(1,n,dfn[t]+1,dfn[v]); return max(max(L.maxv, R.maxv), L.suml+R.suml);}int main(){ //freopen("data.txt","r",stdin); int op, u, v, c; while(~scanf("%d %d",&n,&q)) { for(int i=1; i<=n; i++) { read(a[i]); G[i].clear(); } for(int i=1; i < n; i++) { read(u),read(v); G[u].push_back(v); G[v].push_back(u); } gao(); build(1,n); while(q--) { read(op),read(u),read(v),read(c); if(op==1) change(u,v,c); else write(outputquery(u,v)),putchar('\n'); } } return 0;}
不要求LCA的方法。
#include <bits/stdc++.h>#define MAXN 300500#define lson getidx(l, mid)#define rson getidx(mid + 1, r)using namespace std;typedef long long LL;const LL inf = 0x3f3f3f3f3f3f;struct edge{ int to,next;} E[MAXN*2];int head[MAXN],si,sz[MAXN],top[MAXN],son[MAXN],fa[MAXN],w[MAXN],dep[MAXN], add[MAXN<<1], isupdate[MAXN<<1], N, Q, A[MAXN], idx, mp[MAXN], que[MAXN];struct node{ LL sum,ls,rs,ans; node(LL _ans = 0, LL _sum = 0, LL _ls = 0, LL _rs = 0 ) { ans = _ans; sum = _sum; ls = _ls; rs = _rs; }} tree[MAXN<<1];void add_edge(int u,int v){ E[si].to = v; E[si].next = head[u]; head[u] = si ++;}void bfs(int v){//printf("fa[%d]=%d\n",v,fa[v]); int l = 0, r = 0; for(que[r ++] = v; l < r; l ++) { int now = que[l]; for(int i =head[now]; ~i; i = E[i].next) { int u =E[i].to; if( u == fa[now] )continue; fa[u] = now; dep[u] = dep[now] + 1; que[r ++] = u; } } for(; r; r --) { int now = que[r - 1]; sz[now] = 1; son[now] = 0; for(int i =head[now]; ~i; i = E[i].next) { int u =E[i].to; if( u == fa[now] )continue; sz[now] += sz[u]; if( sz[son[now]] < sz[u] ) { son[now] = u; } } }}void rdfs(int v,int root){ w[v] = ++ idx; mp[idx] = v; top[v] = root; if( son[v] ) rdfs(son[v], root); for(int i =head[v]; ~i; i = E[i].next) { int u = E[i].to; if( u == fa[v] || u == son[v] )continue; rdfs(u,u); }}int getidx(int l,int r){ return l + r | l != r;}void updatenode(node &p, int x, int l, int r){ p = node( x, x * (r - l + 1), x, x ); if( x >= 0) { p = node(x * (r - l + 1), x * (r - l + 1), x * (r - l + 1), x * (r - l + 1)); }}void push_down(int l, int r){ int p =getidx(l, r), mid = l + r >> 1; if( l == r || !isupdate[p] )return; updatenode(tree[lson], add[p], l, mid); updatenode(tree[rson], add[p], mid + 1, r); isupdate[p] = false; isupdate[lson] = true; isupdate[rson] = true; add[lson] = add[rson] = add[p];}node unite(node a, node b){ node p; p.ans = max(a.ans, b.ans); p.ans = max(p.ans, a.rs + b.ls); p.sum = a.sum + b.sum; p.ls = max(a.ls, a.sum + b.ls); p.rs = max(b.rs, b.sum + a.rs); return p;}void put_up(int l, int r){ int p =getidx(l, r), mid = l + r >> 1; if( l == r ) return; tree[p] = unite(tree[lson], tree[rson]);}void build(int l,int r){ int p =getidx(l, r); isupdate[p] = false; add[p] = 0; if( l == r ) { updatenode(tree[p], A[mp[l]], l, r); // printf("[%d,%d]:%lld, %lld ,%lld, %lld\n",l, r,tree[p].ans, tree[p].sum, tree[p].ls, tree[p].rs); return; } int mid = l + r >> 1; build(l, mid); build(mid + 1, r); put_up(l, r); //printf("[%d,%d]:%lld, %lld ,%lld, %lld\n",l, r,tree[p].ans, tree[p].sum, tree[p].ls, tree[p].rs);}void update(int l, int r, int _l, int _r, int x){ if( l > _r || r < _l )return; if( _l <= l && r <= _r ) { int p = getidx(l, r); updatenode(tree[p], x, l, r); add[p] = x; isupdate[p] = true; return; } int mid = l + r >> 1; push_down(l, r); update(l, mid, _l, _r, x); update(mid + 1, r, _l, _r, x); put_up(l, r);}void update(int u,int v,int x){ int a = top[u], b = top[v]; while(a != b) { if( dep[a] < dep[b] ) { swap(a, b); swap(u, v); } update(1, N, w[a], w[u], x); u = fa[a]; a = top[u]; } if( dep[u] < dep[v] ) { swap(u, v); } update(1, N, w[v], w[u], x);}node query(int l, int r, int _l, int _r){ if( _l <= l && r <= _r ) { return tree[getidx(l, r)]; } int mid = l + r >> 1; push_down(l, r); if( _r <= mid ) return query(l, mid, _l, _r); else if( _l > mid ) return query(mid + 1, r, _l, _r); else { return unite(query(l, mid, _l, _r), query(mid + 1, r, _l, _r)); }}LL query(int u, int v){ int a = top[u], b = top[v]; node lpath = node(-inf , 0, -inf, -inf), rpath = node(-inf, 0, -inf, -inf); while(a != b) { if( dep[a] > dep[b]) { node res = query(1, N, w[a], w[u]); swap(res.ls, res.rs); lpath = unite(lpath, res); // printf("lpath:%d->%d: %lld %lld %lld %lld\n", a, u, lpath.ans,lpath.sum, lpath.ls, lpath.rs); u = fa[a]; a = top[u]; } else { node res = query(1, N, w[b], w[v]); rpath = unite(res, rpath); //printf("rpath:%d->%d: %lld %lld %lld %lld\n", b, v, rpath.ans,rpath.sum, rpath.ls, rpath.rs); v = fa[b]; b = top[v]; } } node ans; if( dep[u] < dep[v] ) { ans = query(1, N, w[u], w[v]); } else { ans = query(1, N, w[v], w[u]); swap(ans.ls,ans.rs); } // printf("%d->%d: %lld %lld %lld %lld\n", v, u, ans.ans,ans.sum, ans.ls, ans.rs); ans = unite(lpath, ans); // printf(": %lld %lld %lld %lld\n", ans.ans,ans.sum, ans.ls, ans.rs); ans = unite(ans, rpath); return ans.ans;}int main(){ // freopen("in", "r", stdin); scanf("%d %d", &N, &Q); for(int i = 1; i <= N; i ++) { scanf("%d", &A[i]); } memset(head, -1, sizeof head); si = 0; idx = 0; for(int i = 1, u, v; i < N; i ++) { scanf("%d%d", &u, &v); add_edge(u, v); add_edge(v, u); } fa[1] = dep[1] = 0; bfs(1); rdfs(1, 1); build(1, N); for(int i = 1, t, u, v, x; i <= Q; i ++) { scanf("%d%d%d%d", &t, &u, &v, &x); if( t == 1 ) { update(u, v, x); } else { long long ans = query(u, v); printf("%lld\n", ans); } } return 0;}
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