【字符串反转总结】Java中七种方法实现

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算法比较简单,注释就能说明问题,直接上代码!

方法一:(利用递归实现)

public static String reverse1(String s) {  int length = s.length();  if (length <= 1)   return s;  String left = s.substring(0, length / 2);  String right = s.substring(length / 2, length);  return reverse1(right) + reverse1(left);  //调用递归 }


方法二:(拼接字符串)
public static String reverse2(String s) {  int length = s.length();  String reverse = "";  for (int i = 0; i < length; i++)   reverse = s.charAt(i) + reverse;  return reverse; }

方法三:(利用数组,倒序输出)

public static String reverse3(String s) {  char[] array = s.toCharArray();  String reverse = "";  for (int i = array.length - 1; i >= 0; i--)   reverse += array[i];  return reverse; }

方法四:(利用StringBuffer的内置reverse方法)

public static String reverse4(String s) {  return new StringBuffer(s).reverse().toString(); }

方法五:(利用临时变量,交换两头数值)

public static String reverse5(String orig) {  char[] s = orig.toCharArray();  int n = s.length - 1;  int halfLength = n / 2;  for (int i = 0; i <= halfLength; i++) {   char temp = s[i];   s[i] = s[n - i];   s[n - i] = temp;  }  return new String(s); }

方法六:(利用位异或操作,交换两头数据)具体交换原理,参考上一篇文章

public static String reverse6(String s) {    char[] str = s.toCharArray();    int begin = 0;  int end = s.length() - 1;  while (begin < end) {   str[begin] = (char) (str[begin] ^ str[end]);   str[end] = (char) (str[begin] ^ str[end]);   str[begin] = (char) (str[end] ^ str[begin]);   begin++;   end--;  }  return new String(str); }


方法七:(利用栈结构)

public static String reverse7(String s) {  char[] str = s.toCharArray();  Stack<Character> stack = new Stack<Character>();  for (int i = 0; i < str.length; i++)   stack.push(str[i]);    String reversed = "";  for (int i = 0; i < str.length; i++)   reversed += stack.pop();    return reversed; }
有其它方法,欢迎交流!兰州理工大学

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