LeetCode Invert Binary Tree
来源:互联网 发布:布谷布谷软件 编辑:程序博客网 时间:2024/06/14 02:46
题目:
Invert a binary tree.
4 / \ 2 7 / \ / \1 3 6 9
to 4 / \ 7 2 / \ / \9 6 3 1
题意:将一棵二叉树反转,因为有两种方法,我考虑用非递归的方法来实现。也就是考虑用一个队列LinkedList,然后先将节点依次压入队列中,然后再依次将其pop出现将左子树节点和右字数节点互换。已达到反转的目的。
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */public class Solution { public static TreeNode invertTree(TreeNode root){LinkedList<TreeNode> nodes = new LinkedList<TreeNode>();if(root == null)return root;nodes.push(root);while(!nodes.isEmpty()){TreeNode curr = nodes.peek();nodes.poll();TreeNode pleft = curr.right;curr.right = curr.left; curr.left = pleft; if(curr.left != null) nodes.push(curr.left); if(curr.right != null) nodes.push(curr.right);}return root;}}
此题与之前的二叉树的一些基本的操作雷同,都是用LinkedList来实现层次遍历,然后实现再实现相应的操作。
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