【C++】利用析构统计函数运行时间

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#include <iostream>#include <sys/time.h>using namespace std;class TimeUse {public:TimeUse(string name):_name(name) {gettimeofday(&_time_begin, NULL);}~TimeUse() {gettimeofday(&_time_end, NULL);size_t time_used = (_time_end.tv_sec * 1000 * 1000 + _time_end.tv_usec) - (_time_begin.tv_sec * 1000 * 1000 + _time_begin.tv_usec);cout << "Label : " << _name << "\tTime used : " << time_used << "us" << endl;}private:struct timeval _time_begin;struct timeval _time_end;string _name;};int sum(int num) {int result = 0;for(int i=1; i<num; i++){result += i;}return result;}long long multiply(int num){long long result = 0;for(int i=1; i<num; i++) {result *= i;}return result;}int main(int argc, char const *argv[]) {(TimeUse("Test1"), sum(10000000));(TimeUse("Test2"), sum(50000000));(TimeUse("Test3"), sum(100000000));(TimeUse("Test4"), sum(500000000));//(TimeUse("Test5"), multiply(10000));//(TimeUse("Test6"), multiply(50000));return 0;}

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