1009. Product of Polynomials

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Tips:

  • 本题与1002类似,只不过此题是求乘积,但和1002注意的地方一样.
  • 还需注意的是,本题开辟的数组空间大小应为2001.
#include <iostream>using namespace std;#define LEN 2001int main() {    int k1,k2,i,j,count;    int *pCoe;    double *pIndex;    int coe;    double index;    double *result = new double[LEN];    for(i = 0;i <LEN;i ++)            result[i] = 0;    while(scanf("%d",&k1) != EOF) {        count = 0;        pCoe = new int[k1];        pIndex = new double[k1];        for(i = 0;i < k1;i ++)            scanf("%d %lf",&pCoe[i],&pIndex[i]);        scanf("%d",&k2);        for(i = 0;i < k2;i ++){            scanf("%d %lf",&coe,&index);            for(j = 0;j < k1;j ++){                if(result[coe + pCoe[j]] == 0)                    count ++;                result[coe + pCoe[j]] += index * pIndex[j];                if(result[coe + pCoe[j]] == 0)                    count --;            }        }        printf("%d",count);        for(i = LEN - 1;i >= 0;i --){            if(result[i] != 0){                printf(" %d %.1lf",i,result[i]);                result[i] = 0;            }        }        printf("\n");    }    return 0;}
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