[Leetcode] Word Frequency的笔记

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单词出现的频率


题目如下

Write a bash script to calculate the frequency of each word in a text file words.txt.

For simplicity sake, you may assume:
- words.txt contains only lowercase characters and space ’ ’ characters.
- Each word must consist of lowercase characters only.
- Words are separated by one or more whitespace characters.

For example, assume that words.txt has the following content:
the day is sunny the the
the sunny is is

Your script should output the following, sorted by descending frequency:
the 4
is 3
sunny 2
day 1

Note:

Don’t worry about handling ties, it is guaranteed that each word’s frequency count is unique.


题目大意: 计算每一个单词出现的频率,文件里面包含的是大于等于一个空白字符和小写字母
解题思路: 大体就是对文件的内容进行搜索,排序和统计,那么大体的命令就是grep,sort和uniq的命令来完成

代码如下
grep -Eo "[a-z]*" words.txt|sort -k1|uniq -c|sort -r|awk '{print $2" "$1}'

网上也有其他的答案
cat words.txt \
| tr -s ' ' '\n' \
| awk '{ words[$1]++ } END { for (key in words) print key, words[key] }' \
| sort -rn -k2


总体来说大同小异,扩展一下思路也是一个好事。

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