M1
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A
#include<cstdio>#include<cstdlib>#include<cmath>#include<algorithm>#include<string>#include<cstring>using namespace std;int n;char s[55];int f[55],ans=0;int l[55],ct=0;int main(){ freopen("soccer.in","r",stdin); freopen("soccer.out","w",stdout); scanf("%d",&n); for(int i=1;i<=n;i++){ scanf("%s",s+1); for(int j=1;j<=n;j++){ if(s[j]=='-')continue; else if(s[j]=='W')f[i]+=3; else if(s[j]=='D'){ f[i]+=1; f[j]+=1; } else if(s[j]=='L')f[j]+=3;//每两支队比两次 }// ans=max(ans,f[i]); } for(int i=1;i<=n;i++)ans=max(ans,f[i]); for(int i=1;i<=n;i++){ if(f[i]==ans){ ct++; l[ct]=i; } } for(int i=1;i<ct;i++)printf("%d ",l[i]); printf("%d\n",l[ct]); return 0;}
B
#include<cstdio>#include<cstdlib>#include<cmath>#include<algorithm>#include<string>#include<cstring>using namespace std;int x[1005],y[1005];double dp[1005][1005];double dis[1005][1005];double min(double a,double b){ if(a-b>=0.0)return b; return a;}double Dis(int i,int j){ if(dis[i][j])return dis[i][j]; return dis[i][j]=sqrt(1.0*(x[i]-x[j])*(x[i]-x[j])+1.0*(y[i]-y[j])*(y[i]-y[j]));}int main(){ freopen("paths.in","r",stdin); freopen("paths.out","w",stdout); int n,b1,b2; scanf("%d%d%d",&n,&b1,&b2); for(int i=0;i<n;i++)scanf("%d%d",&x[i],&y[i]); for(int i=0;i<=n;i++) for(int j=0;j<=n;j++) dp[i][j]=999999.0; dp[0][0]=0.0; for(int i=0;i<n;i++){ for(int j=0;j<n;j++){ int k=max(i,j)+1; if(k==n)k--; dp[i][k]=min(dp[i][k],dp[i][j]+Dis(j,k));// MIN dp[k][j]=min(dp[k][j],dp[i][j]+Dis(i,k));// 题解打错了 if(k==b1)dp[i][k]=999999.0;//b1在A线 if(k==b2)dp[k][j]=999999.0;//b2在B线 } } double ans=dp[n-1][n-1]; printf("%.2lf\n",ans); return 0;}
C
//暴力程序 60#include <cstdio>#include <iostream>using namespace std;int n,m;int mp[200009],car[1000009];int main() { freopen("park.in","r",stdin); freopen("park.out","w",stdout); int tot=0; scanf("%d%d",&n,&m); for(int k=1; k<=m; k++) { int f,x; scanf("%d%d",&f,&x); if(f==1) { if(!tot) { printf("1\n"); mp[1]=x; car[x]=1; } else { int last=0,maxlen=-1,ans=1; for(int i=1; i<=n; i++) { if(i==n && !mp[n]) { if(n-last-1>maxlen) { ans=n; } } else if(mp[i]) { if(last==0 && mp[1]==0) { maxlen=i-2; ans=1; } else if((i-last)/2-1>maxlen && i>1) { maxlen=(i-last-2)/2; ans=(i+last)/2; } last=i; } } printf("%d\n",ans); car[x]=ans,mp[ans]=x; } tot++; } if(f==2) { mp[car[x]]=0; tot--; } } return 0;}
0 0
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