leetcode之Letter Combinations of a Phone Number
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这个没什么好说的，就是每个数字代表的字母的排列组合。代码如下：
class Solution(object): def letterCombinations(self, digits): """ :type digits: str :rtype: List[str] """ phonenumber = [[' '], ['*'],['a', 'b', 'c'], ['d', 'e', 'f'], ['g', 'h','i'], ['j', 'k', 'l'], ['m', 'n', 'o'], ['p', 'q','r', 's'], ['t', 'u', 'v'], ['w', 'x', 'y', 'z']] if len(digits) == 0: return [] elif len(digits) == 1: return phonenumber[int(digits)] else: result = phonenumber[int(digits[0])] for i in range(1, len(digits)): m = [] for j in result: for k in phonenumber[int(digits[i])]: m.append(j + k) result = m return result
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