A + B Problem II
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A + B Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 276437 Accepted Submission(s): 53359
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input
21 2112233445566778899 998877665544332211
Sample Output
Case 1:1 + 2 = 3Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110#include<stdio.h>#include<stdlib.h>int main(){ int n,t,i,j,b,start,x,end,end1,start1,a1,max,sum,max1; scanf("%d",&t); for(i=1;i<=t;i++){ scanf("%d%d",&n,&a1); max=a1; max1=a1; start=1; start1=1; end1=1; end=1; printf("Case %d:\n",i); for(j=2;j<=n;j++){ scanf("%d",&b); if(max1<0){ start1=j; end1=j; max1=b; } else { max1+=b; end1=j; } if(max<max1){ max=max1; start=start1; end=end1; } } printf("%d %d %d\n",max,start,end); if(i!=t) printf("\n"); }}
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