[转]通过分析SQL语句的执行计划优化SQL (七)[4]

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0   SELECT STATEMENT Optimizer=CHOOSE (Cost=4 Card=1 Bytes=110)

  1  0  HASH JOIN (Cost=4 Card=1 Bytes=110)

  2  1   NESTED LOOPS (Cost=2 Card=1 Bytes=84)

  3  2    TABLE ACCESS (FULL) OF 'C' (Cost=1 Card=1 Bytes=26)

  4  2    TABLE ACCESS (FULL) OF 'A' (Cost=1 Card=82 Bytes=4756)

  5  1   TABLE ACCESS (FULL) OF 'B' (Cost=1 Card=1 Bytes=26)

  select /*+ USE_NL (A C)*/ A.col4

  from C , A , B

  where C.col3 = 5 and A.col1 = B.col1 and A.col2 = C.col2

  and B.col3 = 10;

  我们这个查询的意思是让A、C表做NL连接,并且让A表作为内表,但是从执行计划来看,没有达到我们的目的。

  Execution Plan

  ----------------------------------------------------------

  0   SELECT STATEMENT Optimizer=CHOOSE (Cost=3 Card=1 Bytes=110)

  1  0  NESTED LOOPS (Cost=3 Card=1 Bytes=110)

  2  1   MERGE JOIN (CARTESIAN) (Cost=2 Card=1 Bytes=52)

  3  2    TABLE ACCESS (FULL) OF 'C' (Cost=1 Card=1 Bytes=26)

  4  2    SORT (JOIN) (Cost=1 Card=1 Bytes=26)

  5  4     TABLE ACCESS (FULL) OF 'B' (Cost=1 Card=1 Bytes=26)

  6  1   TABLE ACCESS (FULL) OF 'A' (Cost=1 Card=82 Bytes=4756)

  对对象进行分析后:

  analyze table a compute statistics;

  analyze table b compute statistics;

  analyze table c compute statistics;

  analyze index inx_col12A compute statistics;

  select A.col4

  from C , A , B

  where C.col3 = 5 and A.col1 = B.col1 and A.col2 = C.col2

  and B.col3 = 10;

  Execution Plan

  ----------------------------------------------------------

  0   SELECT STATEMENT Optimizer=CHOOSE (Cost=5 Card=8 Bytes=336)

  1  0  HASH JOIN (Cost=5 Card=8 Bytes=336)

  2  1   MERGE JOIN (CARTESIAN) (Cost=3 Card=8 Bytes=64)

  3  2    TABLE ACCESS (FULL) OF 'B' (Cost=1 Card=2 Bytes=8)

  4  2    SORT (JOIN) (Cost=2 Card=4 Bytes=16)

  5  4     TABLE ACCESS (FULL) OF 'C' (Cost=1 Card=4 Bytes=16)

  6  1   TABLE ACCESS (FULL) OF 'A' (Cost=1 Card=30 Bytes=1020)

  select /*+ ORDERED */ A.col4

  from C , A , B

  where C.col3 = 5 and A.col1 = B.col1 and A.col2 = C.col2

  and B.col3 = 10;

  Execution Plan

  ----------------------------------------------------------

  0   SELECT STATEMENT Optimizer=CHOOSE (Cost=5 Card=9 Bytes=378)

  1  0  HASH JOIN (Cost=5 Card=9 Bytes=378)

  2  1   HASH JOIN (Cost=3 Card=30 Bytes=1140)

  3  2    TABLE ACCESS (FULL) OF 'C' (Cost=1 Card=4 Bytes=16)

  4  2    TABLE ACCESS (FULL) OF 'A' (Cost=1 Card=30 Bytes=1020)

  5  1   TABLE ACCESS (FULL) OF 'B' (Cost=1 Card=2 Bytes=8)

  select /*+ ORDERED USE_NL (A C)*/ A.col4

  from C , A , B

  where C.col3 = 5 and A.col1 = B.col1 and A.col2 = C.col2

  and B.col3 = 10;

  Execution Plan

  ----------------------------------------------------------

转自 http://it.educity.cn/oracle/200712281702191014.htm 
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