leetcode-Majority Element
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用哈希表保存出现的次数即可。
public class Solution { public int majorityElement(int[] nums) { int max=0,result=0,curLen=0; HashMap<Integer,Integer> ha=new HashMap<Integer,Integer>(); for(int i=0;i<nums.length;i++) { if(!ha.containsKey(nums[i])) ha.put(nums[i], 1); else { curLen=ha.get(nums[i]); curLen++; ha.put(nums[i], curLen); } curLen=ha.get(nums[i]); if(curLen>max) { max=curLen; result=nums[i]; } } return result; }} 0 0
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