例4-2 UVa489 Hangman Judge

要点：
1.利用一个left变量判断还剩几个字母，用chance判断还能猜几次，原来chance放在开头导致一直WA

#include<stdio.h>#include<string.h>#define maxn 100char s[maxn], s2[maxn];int left, chance,t;int win, lose;void guess(char ch){    int bad = 1;    for (int i = 0; i < strlen(s); i++)    {        if (ch == s[i])//若猜中一个字母在字符串中所有该字母都会显露出来        {            left--;            s[i] = ' ';//未防止已经猜出的字母干扰，将已猜出的赋值为空格            bad = 0;        }    }    if (bad)  chance--;    if (chance == 0) lose = 1;    if (left == 0)  win = 1;}int main(){    while (scanf("%d", &t),t != -1)    {           chance = 7;//值都应该放在循环中        scanf("%s%s", s, s2);        win = lose = 0;        left = strlen(s);        printf("Round %d\n", t);        for (int i = 0; i < strlen(s2); i++)        {            guess(s2[i]);            if (win || lose)                break;        }        if (win) printf("You win.\n");        else if (lose)  printf("You lose.\n");        else printf("You chickened out.\n");    }    return 0;}

学习心得：
1.要多次判断比较的值要放在循环中