杭电1037——Keep on Truckin'（简单题）

题目描述

Problem Description
Boudreaux and Thibodeaux are on the road again …

“Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!”

“Don’t worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!”

“We’re not going to make it, I say!”

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

Input
Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

Output
There will be exactly one line of output. This line will be:

NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.

Sample Input
180 160 170

Sample Output
CRASH 160

题意大致翻译

让你输入三个地下隧道的高度，已知货车的高度为168，如果地下隧道的高度都大于货车高度（168），则输出NO CRASH，否则，若是某条隧道的高度低于或者等于货车的高度，则输出CRASH X，其中X是该隧道的高度。

题目很简单，看懂题意就行~

AC代码

# include<stdio.h>int main(){    int a,b,c;    scanf("%d%d%d",&a,&b,&c);    if(a>168&&b>168&&c>168)        printf("NO CRASH\n");    else    {        if(a<=168)            printf("CRASH %d\n",a);        if(b<=168)            printf("CRASH %d\n",b);        if(c<=168)            printf("CRASH %d\n",c);    }    return 0;}