Unix学习笔记------实例练习---Day02_access函数文件访问权限测试

来源:互联网 发布:c语言初始化是什么意思 编辑:程序博客网 时间:2024/06/05 00:16

Day02_access函数文件访问权限测试

::::::::::

 

/*

         access()函数,文件访问权限测试,

         能测试这个进程是否有权限访问这个文件。

        

         access函数原型:

         ::::::::::::

                    access - check real user鈥檚permissions for a file

 

SYNOPSIS

      #include <unistd.h>

 

      int access(const char *pathname, int mode);

 

DESCRIPTION

      access() checks whether the calling process can access the filepathname.  If pathname is a symboliclink, it is dereferenced.

 

      The  mode  specifies the  accessibility check(s) to beperformed, and is either the value F_OK, or a mask consisting of the bitwise ORof one or more of R_OK, W_OK, and

      X_OK.  F_OK tests for theexistence of the file.  R_OK, W_OK, andX_OK test whether the file exists and grants read, write, and executepermissions, respectively.

 

      The check is done using the calling process鈥檚 real UIDand GID, rather than the effective IDs as is done when actually attempting anoperation  (e.g.,  open(2)) on  the

      file.  This allows set-user-IDprograms to easily determine the invoking user鈥檚 authority.

 

      If  the  calling process is privileged (i.e., its real UID is zero), then an X_OK checkis successful for a regular file if execute permission is enabled for any ofthe

      file owner, group, or other.

 

RETURN VALUE

      On success (all requested permissions granted), zero is returned.  On error (at least one bit in mode askedfor  a permission  that  is denied,  or  some other  error

      occurred), -1 is returned, and errno is set appropriately.

 

ERRORS

      access() shall fail if:

 

      EACCES The  requested access wouldbe denied to the file, or search permission is denied for one of thedirectories in the path prefix of pathname. (See also path_reso-

              lution(7).)

 

      ELOOP  Too many symbolic linkswere encountered in resolving pathname.

 

      ENAMETOOLONG

              pathname is too long.

 

      ENOENT A component of pathname does not exist or is a dangling symboliclink.

 

      ENOTDIR

              A component used as a directoryin pathname is not, in fact, a directory.

 

      EROFS  Write permission wasrequested for a file on a read-only file system.

 

      access() may fail if:

 

      EFAULT pathname points outside your accessible address space.

 

      EINVAL mode was incorrectly specified.

 

      EIO    An I/O error occurred.

 

      ENOMEM Insufficient kernel memory was available

        

         :::::::::::::::::::::

*/

 

 

测试实例源代码:

用该进程创建一个my.txt 文件,然后用access()函数测试。

 

 

程序源代码:

 

 

 

#include<unistd.h>

#include<fcntl.h>

#include<stdio.h>

#include<error.h>

#include<errno.h>

int main()

{

         int  access_returnvalue ;

         access_returnvalue=access("/home/code/file1/my.txt",R_OK);

         if(access_returnvalue!=-1)

         printf("theaccessiblity of reading is not ok\n");

         printf("theread accessibility is :%d\n",access_returnvalue);

        

         access_returnvalue=access("/home/code/file1/my.txt",W_OK);

         if(access_returnvalue!=-1)

         printf("thewrite is allowed");

         printf("THERETURN VALUE IS :%d \n",access_returnvalue);

        

      return 0;

 

        

        

}

 

 

程序运行截图:

 

0 0
原创粉丝点击