[LeetCode] Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

解题思路

让当前结点的值等于下一节点的值，然后当前结点指向下一节点的下一节点，最后删除要删掉结点的下一节点。

实现代码

// Runtime: 1 ms/** * Definition for singly-linked list. * public class ListNode { *     int val; *     ListNode next; *     ListNode(int x) { val = x; } * } */public class Solution {    public void deleteNode(ListNode node) {        node.val = node.next.val;        node.next = node.next.next;    }}