使用struts的Ajax支持

来源：互联网发布：抓取ajax动态网页java 编辑：程序博客网时间：2024/06/05 16:39

ActionTest.java

package com.ztx.action;

import java.io.ByteArrayInputStream;

import java.io.InputStream;

import java.io.UnsupportedEncodingException;

import com.opensymphony.xwork2.ActionSupport;

public classActionTest extends ActionSupport {

private InputStreaminputStream;

private StringnameId;

public String getNameId() {

return nameId;

}

public void setNameId(StringnameId) {

try {

//%df%a4转换为字符串，即使用指定的编码机制对 application/x-www-form-urlencoded 字符串解码

this.nameId = java.net.URLDecoder.decode(nameId,"UTF-8");

}catch(UnsupportedEncodingException e) {

e.printStackTrace();

}

public InputStreamgetInputStream() {

return inputStream;

}

public String execute()throws Exception {

if (nameId.equals("zhangsan")){

inputStream = new ByteArrayInputStream("用户名正确".getBytes("utf-8"));

}else{

inputStream = new ByteArrayInputStream("用户名不存在".getBytes("utf-8"));

}

return SUCCESS;

}

struts.xml

<?xmlversion="1.0"encoding="UTF-8"?>

<!DOCTYPEstruts PUBLIC

"-//Apache Software Foundation//DTD StrutsConfiguration 2.3//EN"

"http://struts.apache.org/dtds/struts-2.3.dtd">

<constantname="struts.configuration.xml.reload"value="true"/>

<packagename="ztx"extends="struts-default">

<actionname="testAjax"class="com.ztx.action.ActionTest">

<resulttype="stream">

<paramname="contentType">application/octet-stream</param>

<paramname="inputName">inputStream</param>

</result>

</action>

</package>

</struts>

<%@ page language="java"import="java.util.*"pageEncoding="utf-8"%>

Stringpath = request.getContextPath();

StringbasePath = request.getScheme() + "://"

+request.getServerName() + ":" + request.getServerPort()

+path + "/";

<!DOCTYPEHTML PUBLIC "-//W3C//DTDHTML 4.01 Transitional//EN">

<html>

<head>

<basehref="<%=basePath%>">

<title>My JSP'index.jsp' starting page</title>

<metahttp-equiv="pragma"content="no-cache">

<metahttp-equiv="cache-control"content="no-cache">

<metahttp-equiv="expires"content="0">

<metahttp-equiv="keywords"content="keyword1,keyword2,keyword3">

<metahttp-equiv="description"content="This is my page">

<!--

<linkrel="stylesheet" type="text/css"href="styles.css">

-->

<scripttype="text/javascript">

var xmlHttp;

function validate() {

var idField = document.getElementById("userName");

// varxhrUrl = "DoAjaxServlet.do?nameId="+escape(idField.value);

//这样写的后果就是：

//如果传递中文，就会抛出异常

//警告: Parameters: Character decoding failed. Parameter skipped.
//java.io.CharConversionException: isHexDigit.

var xhrUrl ="testAjax.action?nameId=" + idField.value;

xhrUrl = encodeURI(xhrUrl); //写一个不行。如果写一个就是？？？？号。

xhrUrl = encodeURI(xhrUrl); //写2个，则输出%df%a4这中.application/x-www-form-urlencoded字符串

if (window.XMLHttpRequest) {

xmlHttp = new XMLHttpRequest();

} else {

xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");

}

xmlHttp.open("get", xhrUrl,true);

xmlHttp.onreadystatechange =callback;

xmlHttp.send();

}

function callback() {

if (xmlHttp.readyState == 4 &&xmlHttp.status == 200) {

document.getElementById("info").innerHTML =xmlHttp.responseText;

}

</script>

</head>

<body>

<formaction=""method="post">

<inputtype="text"id="userName"name="userName"onblur="validate()"/>

<divid="info"></div>

<br/> <inputtype="text"id="password"name="password"/><br/> <input

type="submit"value="提交">

</form>

</body>

</html>

2 0