hdu 2199 Can you solve this equation?

Can you solve this equation?

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 13855    Accepted Submission(s): 6185

Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.

 

Input

The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

 

Output

For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

 

Sample Input

2100-4

 

Sample Output

1.6152No solution!
题型：二分查找
注意，，double型数据不能直接用等号，而应该作使差的绝对值小于一个足够小的数，，水题
#include<iostream>#include<cstdio>#include<cstring>#include<math.h>using namespace std;double y;double f(double x){    return 8*x*x*x*x+7*x*x*x+2*x*x+3*x+6-y;}int main(){    int cas;    scanf("%d",&cas);    while(cas--)    {       scanf("%lf",&y);       if(f(0)>0||f(100)<0)       {          printf("No solution!\n");          continue;       }       double m,l=0,r=100;       while(r-l>=1e-8)       {            m=(l+r)/2.0;            if(f(m)<0)               l=m;            else               r=m;            if(fabs(f(m))<1e-8)               break;       }       printf("%.4lf\n",m);    }    return 0;}