【Leetcode】Permutations

来源:互联网 发布:淘宝怎么赚佣金 编辑:程序博客网 时间:2024/05/29 17:07

题目链接:https://leetcode.com/problems/permutations/

题目:

Given a collection of numbers, return all possible permutations.

For example,
[1,2,3] have the following permutations:
[1,2,3][1,3,2][2,1,3][2,3,1][3,1,2], and [3,2,1].

o see which companies asked this question

思路:

数组下标的三皇后问题,实质是全排列问题。唯一不同 都是,本题全排列的是数组的下标。只要做个对应转化就好了。

算法:

List<List<Integer>> iLists = new ArrayList<List<Integer>>();public List<List<Integer>> permute(int[] nums) {this.n = nums.length;this.cl = new int[n];this.n2 = nums;dspPermute(0);return iLists;}int[] n2;int cl[] = null;int n = 0;void dspPermute(int cur) {if (cur == n) {List<Integer> list = new ArrayList<Integer>();for (int i = 0; i < cl.length; i++) {list.add(cl[i]);}iLists.add(list);} else {for (int i = 0; i < n; i++) { // 探索每一列cl[cur] = n2[i];// 选择n[i]为第cur个数boolean flag = true;for (int j = 0; j < cur; j++) {// cur前所有行 若无冲突if (cl[cur] == cl[j])flag = false;}if (flag == true) {dspPermute(cur + 1);}}}}


0 0
原创粉丝点击